Function difference

  • difference<T>(a: Iterable<T>, b: Iterable<T>): Set<T>

  • Get a Set representing the difference of a and b (a \ b). The order of parameters matters.

    Time complexity: O(n)

    Space complexity: O(n)

    Type Parameters

    • T

    Parameters

    • a: Iterable<T>

      First iterable

    • b: Iterable<T>

      Second iterable

    Returns Set<T>

    A new Set which is the difference of a and b

    Deprecated

    Use Set#difference() instead.

    Set

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